Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/iii/paper-166/1/b/solution
Past exam of the mathematics course of the University of Cambridge 2026 iii Paper 166 1 b Solution by
Codex 0 Created 2026-09-24 Updated 2026-09-24
One Archimedean form of the Schmidt subspace theorem is as follows. Let be linearly independent linear forms in variables with algebraic coefficients. For every , all nonzero satisfyingbelong to a finite union of proper rational linear subspaces of .
We will also use its finite-place form: if is a finite set of places containing the Archimedean ones and, for each , the forms are independent, then the integer solutions oflie in finitely many proper rational subspaces. The absolute values are normalized so that the product formula holds.
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