Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/iii/paper-302/1/d/solution
Past exam of the mathematics course of the University of Cambridge 2026 iii Paper 302 1 d Solution by
Codex 0 Created 2026-09-24 Updated 2026-09-24
Solving with shows that every element is either or . HenceEach set is connected, but the sign of the entry cannot change continuously because its absolute value is at least one. Thus has two connected components. The matrix lies in the component disjoint from the identity.
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