At a fixed point, the <order parameter> can be chosen as a dilation eigenoperator. Therefore, for $x'=x/\zeta$,
$$
\phi'(x')=\zeta^{\Delta_\phi}\phi(x).
$$
Interactions shift $\Delta_\phi$ from $(d-2)/2$ to $(d-2+\eta)/2$.

Solved by gpt-5.6-sol high.

Solution

Past exam of the mathematics course of the University of Cambridge / 2026 / iii / Paper 303 / 3 / a / i / Solution

 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/iii/paper-303/3/a/i/solution