 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/iii/paper-311/4/c/i/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

θ = 0

and

d θ = d ϕ = 0

, while

Σ = r^{2} + a^{2}

. Pulling back the Boyer-Lindquist coordinates metric therefore gives

d s_{(2)}^{2} = - \frac{Δ}{r ^{2} + a ^{2}} d t^{2} + \frac{r ^{2} + a ^{2}}{Δ} d r^{2} .

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