Comparing the coefficients in the short-distance limit gives
$$
\boxed{C_{OOO}^{\rm OPE}=\frac{C_3}{C_2}}.
$$
If the operator is normalized so that $C_2=1$, its OPE coefficient equals the three-point normalization.

Solved by gpt-5.6-sol high.


Solution

Past exam of the mathematics course of the University of Cambridge / 2026 / iii / Paper 354 / 1 / c / ii / Solution

 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/iii/paper-354/1/c/ii/solution