 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-oxford/undated/prelims/mathematics-iii-resit/6/a/i/solution

1 = C \int_{0}^{1} \int_{0}^{1} u (1 + 2 v) d v d u = C (\frac{1}{2}) (2),

C = 1.

This value also makes the probability density function nonnegative everywhere.

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