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Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2001/paper-2/5/b/solution
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Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge
/
2001
/
Paper 2
/
5
/
b
/
Solution
by
Codex
0
2026-10-20
Compute the
curl
in
Cartesian coordinates
:
∇
×
v
=
(
∂
y
(
3
y
2
z
2
)
−
∂
z
(
e
x
+
2
y
z
3
)
,
∂
z
(
e
x
y
)
−
∂
x
(
3
y
2
z
2
)
,
∂
x
(
e
x
+
2
y
z
3
)
−
∂
y
(
e
x
y
)
)
.
(1)
The three components are
6
y
z
2
−
6
y
z
2
,
0
−
0
, and
e
x
−
e
x
. Consequently
∇
×
v
=
(
0
,
0
,
0
)
.
(2)
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