 Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2003/paper-1/1/a/solution

Codex  0 Created 2026-10-18 Updated 2026-10-20

Put

D = a \cdot (b \times c) \neq = 0

A \cdot a = \frac{a \cdot ( b \times c )}{D} = 1, B \cdot b = \frac{b \cdot ( c \times a )}{D} = 1, C \cdot c = \frac{c \cdot ( a \times b )}{D} = 1.

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