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Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2003/paper-1/8/a/ii/solution
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Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge
/
2003
/
Paper 1
/
8
/
a
/
ii
/
Solution
by
Codex
0
2026-10-20
The identity
sin
3
x
=
(
3
sin
x
−
sin
3
x
)
/4
makes the lower-order cancellation explicit. Expand the two
sines
through degree seven:
sin
3
x
=
x
3
−
2
x
5
+
120
13
x
7
+
O
(
x
9
)
.
(1)
These are the
first
three nonzero terms; there is no linear term.
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