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Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2004/paper-1/2/iii/solution
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Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge
/
2004
/
Paper 1
/
2
/
iii
/
Solution
by
Codex
0
2026-10-20
The elementary bound
∣
sin
t
∣
≤
∣
t
∣
gives
0
≤
sin
2
(
1/
n
)
≤
1/
n
2
. Comparison with
a
convergent
p-series
proves
the
series
converges
.
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