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Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2004/paper-1/6/ii/solution
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Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge
/
2004
/
Paper 1
/
6
/
ii
/
Solution
by
Codex
0
2026-10-20
For
k
=
1
, the required right-hand
matrix
has twice the
first
row of
A
, the same
second
row, and twice the third row. Left
multiplication
scales rows, so
B
=
diag
(
2
,
1
,
2
)
.
(1)
Equivalently, right multiply the given
equation
B
A
=
C
by
A
−
1
to obtain the same answer.
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:
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