Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2006/paper-1/10/c/solution
Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge 2006 Paper 1 10 c Solution by
Codex 0 Created 2026-10-18 Updated 2026-10-20
The differential operator is , where . Set ; the product rule reduces the equation to . Twice integrating gives . The initial conditions yield , soThis substitution removes the repeated characteristic root before finding a particular solution.
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