Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2006/paper-2/7/c/solution

The cross derivatives are both , so the equation is exact. The function differentiates to the given one-form. Hence
Differentiating this implicit equation checks both coefficients of the exact differential directly.

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