 Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2007/paper-2/section-a/2/b/solution

Using

d (sin^{2} x) / d x = 2 sin x cos x

J = [\frac{1}{2} sin^{2} x]_{0}^{π /2} = \frac{1}{2} .

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