 Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2008/paper-2/16/a/iii/solution

Codex  0 Created 2026-10-18 Updated 2026-10-20

Since

A^{2} A = A^{3} = I = A A^{2}

(A^{2})^{- 1} = A .

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