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Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2010/paper-2/18/a/solution
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Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge
/
2010
/
Paper 2
/
18
/
a
/
Solution
by
Codex
0
2026-10-18
Split the
integrand
into its three coordinate contributions. Each integrates independently over the rectangular box:
I
=
(
3
2
)
(
4
)
(
6
)
+
(
2
)
(
3
16
)
(
6
)
+
(
2
)
(
4
)
(
18
)
=
16
+
64
+
144
=
224
.
(1)
For example, the last factor is
∫
−
3
3
z
2
d
z
=
18
. No spherical or cylindrical
Jacobian
is needed for this Cartesian
integral
.
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