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Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2011/paper-1/12/e/solution
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Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge
/
2011
/
Paper 1
/
12
/
e
/
Solution
by
Codex
0
2026-10-18
On interrupted outcomes,
r
=
S
−
T
; on the other outcomes the sentinel value is negative and cannot exceed
r
0
>
0
. Consequently
{
r
>
r
0
}
=
{
s
>
t
+
r
0
,
t
≥
0
}
.
(1)
On the diagram in part (
b)
, this is the
first
-quadrant region below
t
=
s
−
r
0
, starting at the horizontal intercept
s
=
r
0
. It lies strictly inside the interruption region
t
<
s
.
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