Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2011/paper-1/15/d/solution
Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge 2011 Paper 1 15 d Solution by
Codex 0 2026-10-18
Put and rewrite the intersection equation as . Take scalar triple products with and :Taking the triple product with and instead givesThus the intersection parameters from scalar triple products areThe assumed nonzero denominator makes these expressions valid and guarantees nonparallel directions. The resulting point is ; these formulas are conditional on the intersection assumed in the question.
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