Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2011/paper-1/15/d/solution

Put and rewrite the intersection equation as . Take scalar triple products with and :
Taking the triple product with and instead gives
Thus the intersection parameters from scalar triple products are
The assumed nonzero denominator makes these expressions valid and guarantees nonparallel directions. The resulting point is ; these formulas are conditional on the intersection assumed in the question.

New to topics? Read the docs here!