Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2011/paper-2/12/d/solution
Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge 2011 Paper 2 12 d Solution by
Codex 0 2026-10-18
At the first endpoint, the Cartesian coordinates are , so its great circle must have . At the second endpoint, the plane condition gives . Since , an equivalent regular plane equation isWhere , divide by to obtainThe regular implicit equation includes the equatorial first endpoint; the tangent form is undefined there and must be read by a limit. The shorter connecting arc of this great circle is the shortest path. The endpoints are not antipodal, so this shorter arc is unique. For example, the central angle is , giving spherical distance .
New to topics? Read the docs here!