Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2012/paper-1/9/a/solution
Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge 2012 Paper 1 9 a Solution by
Codex 0 2026-10-18
The domain of a function is , because the denominator vanishes at zero. Near zero, , so is a vertical asymptote, approached with value from the left and from the right. The horizontal asymptotes are as and as .
Moreover,Both branches define a strictly decreasing monotone function: the left branch lies below , and the right branch is positive. There are no zeros or vertical-axis intercept.
The decreasing reciprocal-exponential branches with their three asymptotes
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