 Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2013/paper-1/4/solution

x = 3

, the point on the parabola is

(3, 8)

f^{'} (3) = 6

- 1/6

. Its equation is

y - 8 = - \frac{1}{6} (x - 3), y = - \frac{x}{6} + \frac{17}{2} .

Thus the requested results are

gradient - \frac{1}{6}, vertical-axis intercept (0, 17/2) .

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