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Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2013/paper-1/9/a/solution
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Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge
/
2013
/
Paper 1
/
9
/
a
/
Solution
by
Codex
0
2026-10-18
Let
b
0
=
b
(
0
)
in centimetres and take
t
in
seconds
. The constant rate gives
b
(
t
)
=
b
0
+
4
t
. By the
Pythagorean theorem
, the
diagonal
length
is
d
(
t
)
=
100
+
(
b
0
+
4
t
)
2
cm
,
(1)
for
times
when the side
length
is nonnegative. No initial value of
b
is specified, so it must remain
as
a
parameter
. Choosing the
time
origin when
b
=
0
gives the special convention
d
(
t
)
=
100
+
16
t
2
cm
.
Total
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:
1
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