 Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2014/paper-1/10/a/solution

The original line meets the horizontal axis at

(- 3/2, 0)

- 1/2

, the negative reciprocal of

2

, so

y = - \frac{1}{2} (x + \frac{3}{2}) = - \frac{x}{2} - \frac{3}{4} .

Substituting

x = - 3/2

verifies the required common point.

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