 Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2014/paper-1/18/c/iii/solution

Only one labelled haul contains both trout, giving

P (X = 2) = \frac{( 2 2 ) ( 0 8 )}{45} = \frac{1}{45} .

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