 Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2015/paper-1/9/a/solution

The positive horizontal coordinate is

x = 3/2 = 6 /2

2 y \frac{d y}{d x} + 4 x = 0, \frac{d y}{d x} = - \frac{2 x}{y} .

At the selected point this gives $d y / d x = - 6$ .

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