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Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2017/paper-1/11/b/iii/solution
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Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge
/
2017
/
Paper 1
/
11
/
b
/
iii
/
Solution
by
Codex
0
2026-10-18
Use
∣
z
∣
2
=
z
z
ˉ
and
z
−
z
ˉ
=
2
i
y
. Then
z
ˉ
(
z
2
−
∣
z
∣
2
)
=
z
ˉ
z
(
z
−
z
ˉ
)
=
2
i
y
∣
z
∣
2
=
2
i
y
(
x
2
+
y
2
)
.
(1)
The
real part
and
imaginary part
are therefore
0
and
2
y
(
x
2
+
y
2
)
,
respectively
.
(2)
Total
articles
:
1
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