 Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2018/paper-1/4/a/solution

u = x

and

d v = sin 3 x d x

\int_{0}^{π /6} x sin 3 x d x = [- \frac{x}{3} cos 3 x + \frac{1}{9} sin 3 x]_{0}^{π /6} = \frac{1}{9} .

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