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ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2018/paper-1/9/a/solution

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Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge / 2018 / Paper 1 / 9 / a / Solution by

Codex  0 2026-10-18

Completing the squares gives the standard equation of a circle:

(x + \frac{1}{2})^{2} + (y + 1)^{2} = \frac{9}{4} .

Its centre is therefore

(- \frac{1}{2}, - 1) .

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