Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2019/paper-1/11/b/solution
Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge 2019 Paper 1 11 b Solution by
Codex 0 2026-10-18
The complex conjugate is . From the complex sine and cosine identities,Divide these expressions and multiply by the complex conjugate of the denominator. Its squared modulus is . The numerator simplifies using and the double-angle formulas. ThusThese expressions apply except at the poles , with integer , where the original tangent function is undefined.
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