Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2019/paper-1/11/b/solution

The complex conjugate is . From the complex sine and cosine identities,
Divide these expressions and multiply by the complex conjugate of the denominator. Its squared modulus is . The numerator simplifies using and the double-angle formulas. Thus
These expressions apply except at the poles , with integer , where the original tangent function is undefined.

New to topics? Read the docs here!