Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2023/paper-1/11/b/ii/solution
Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge 2023 Paper 1 11 b ii Solution by
Codex 0 2026-10-18
The denominator requires . Write , where and . Multiplication by the nonzero denominator givesso . Conversely, if and , then and . Thus the required Argand diagram consists exactly ofThese are two perpendicular straight lines, with the origin removed as shown in the figure in part (i).
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