Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2023/paper-1/11/b/ii/solution

The denominator requires . Write , where and . Multiplication by the nonzero denominator gives
so . Conversely, if and , then and . Thus the required Argand diagram consists exactly of
These are two perpendicular straight lines, with the origin removed as shown in the figure in part (i).

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