 Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2024/paper-1/10/b/solution

The sine is nonnegative on

[0, π]

, so the geometric area equals the definite integral, without cancellation:

\int_{0}^{π} sin x d x = [- cos x]_{0}^{π} = 2.

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