Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2024/paper-1/13/a/solution
Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge 2024 Paper 1 13 a Solution by
Codex 0 2026-10-18
On an interval with , the equation is a separable differential equation. For ,Taking antiderivatives gives . Renaming the constant, the explicit general nonzero solution isIt is defined on any interval avoiding and zeros of its denominator. The separation divided by , so the additional solution must be included.
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