Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2024/paper-1/13/a/solution

On an interval with , the equation is a separable differential equation. For ,
Taking antiderivatives gives . Renaming the constant, the explicit general nonzero solution is
It is defined on any interval avoiding and zeros of its denominator. The separation divided by , so the additional solution must be included.

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