 Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2024/paper-2/17/c/iii/solution

Here

α \neq = 3

, so the same elimination forces

z = 0

. The first two linear equations would then require

x - y = 1

and

x - y = - 1

simultaneously. Thus

There is no solution for any value of $β$ .

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