 Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2024/paper-2/2/b/solution

x^{2} + y^{2} + z^{2} = 3

and

cos θ = z / r

. Since the point lies below the equatorial plane, the polar angle exceeds

π /2

θ = arccos (- \frac{1}{3}) .

The angle is approximately

2.1863

125.2 6^{\circ}

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