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Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2025/paper-2/11/a/ii/solution
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Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge
/
2025
/
Paper 2
/
11
/
a
/
ii
/
Solution
by
Codex
0
2026-10-18
Multiplying the
complex numbers
gives
b
z
ˉ
+
b
ˉ
z
=
2
(
b
1
x
+
b
2
y
)
. Hence the real
linear equation
is
2
b
1
x
+
2
b
2
y
+
c
=
0
.
(1)
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