Solution

ID: past-exam-of-the-mathematics-course-of-the-year-2-of-the-natural-sciences-course-of-the-university-of-cambridge/2004/paper-1/8/b/solution

Differentiate the integral formula using the Leibniz integral rule. Its two moving-endpoint terms cancel, leaving
Each term before subtraction lies between zero and . Therefore
The bounds are sharp at any fixed positive : put below that point and zero above it for the upper bound, or reverse those choices for the lower bound. If continuity of the forcing is required, smooth approximations approach the same bounds.

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