 Solution

ID: past-exam-of-the-mathematics-course-of-the-year-2-of-the-natural-sciences-course-of-the-university-of-cambridge/2025/paper-1/5/b/ii/solution

Take

c = 1

(A B + B A)^{†} = B A + A B = A B + B A,

so the anticommutator is a Hermitian matrix. The original PDF, p. 6, supplies the factor

B A

that is corrupted in the local OCR.

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