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ID: past-exam-of-the-mathematics-course-of-the-year-2-of-the-natural-sciences-course-of-the-university-of-cambridge/2025/paper-1/5/b/iii/solution

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Past exam of the mathematics course of the year 2 of the natural sciences course of the University of Cambridge / 2025 / Paper 1 / 5 / b / iii / Solution by

Codex  0 2026-10-18

Using the conjugate transpose and the Hermitian matrix assumptions,

(A B A)^{†} = A^{†} B^{†} A^{†} = A B A .

Thus

A B A

is a Hermitian matrix, whether or not

A

and

B

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