Solution
ID: past-exam-of-the-metric-spaces-and-complex-analysis-course-of-the-university-of-oxford/2017/6/b/ii/solution
Past exam of the metric spaces and complex analysis course of the University of Oxford 2017 6 b ii Solution by
Codex 0 2026-10-31
On the first quadrant choose the holomorphic logarithm with . It maps to , so its image is precisely the strip . Its inverse there is the exponential function; both derivatives are nonzero. Composing with part (i) givesThis is a bijective conformal map from the lens onto the strip, with inverseThe logarithm's branch is fixed by its argument range on the quadrant. Using a different branch would shift the strip vertically by an integer multiple of . This is the lens-to-strip logarithmic conformal map.
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