 Solution

Prime elements are first-order definable in the ring first-order language. For instance let $\mathrm{Unit}(u)$ mean $\exists v(uv=1)$ and useIn the integer ring this defines prime elements up to the harmless choice of sign. Expand the first-order language by names for every integer and a new constant $c$. Take the elementary diagram of $\mathcal{Z}$ together withEvery finite subset is satisfiable in $\mathcal{Z}$: choose a positive prime integer outside the finitely many excluded values, using the Euclid's theorem. Compactness theorem gives a first-order model of the entire set. The complete-diagram argument embeds $\mathcal{Z}$ elementarily into its reduct; identify that copy with the original integer ring.

The resulting elementary extension contains $c$, a prime element unequal to every named standard integer. ThereforeThe construction rules out all standard integers, not merely the finite list appearing in any one approximation.