 Solution

Use the complete theory of dense linear orders without endpoints in the first-order language $\{<\}$. It eliminates quantifiers: existential conditions on one new point reduce to finitely many logical equality constraints and interval bounds, and density and absence of endpoints decide whether a suitable point exists. Its countably infinite first-order models are all isomorphic to the rational order by the usual back-and-forth method, extending finite order-preserving maps alternately along enumerations of the two first-order models. Thus it is ${\aleph }_0$-categorical.

To distinguish first-order models of size ${\aleph }_1$, letwith ordered sums. Both are dense without endpoints and have cardinality ${\aleph }_1$. The first has cofinality ${\aleph }_1$: countably many points lie in a bounded set of block indices and cannot be cofinal. The second has cofinality ${\aleph }_0$, supplied by its final rational block. Cofinality of a linear order is preserved by isomorphism, so they are not isomorphic. ThereforeFor Ryll-Nardzewski, its $n$-types are precisely the finitely many equality-and-order patterns on $n$ coordinates. Each is isolated by the conjunction specifying that pattern, agreeing with the theorem's prediction.