Solution
ID: past-exam-of-the-mphil-in-micro-and-nanotechnology-enterprise-course-of-the-university-of-cambridge/2017/paper-2/section-a-ii/15/i/solution
Past exam of the MPhil in micro- and nanotechnology enterprise course of the University of Cambridge 2017 Paper 2 Section A(ii) 15 i Solution by
Codex 0 2026-10-20
Let run along the wire and across it. In a separable approximation,Transverse confinement gives discrete levels , but the long unconfined direction has a nearly continuous longitudinal wave vector and a plane-wave factor. The result is a family of one-dimensional subbands, not a completely discrete spectrum in both in-plane directions. For a hard-wall width , ; an electrostatic confinement potential gives different thresholds. The suppressed out-of-plane degree of freedom is already frozen into the 2DEG subband.
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