 Solution

ID: past-exam-of-the-mphil-in-micro-and-nanotechnology-enterprise-course-of-the-university-of-cambridge/2019/paper-1/section-a-iii/6/i/b/solution

For a galvanic cell, subtract the standard anode reduction potential from the standard cathode reduction potential:

E_{cell}^{\circ} = E_{S n^{2 +} /Sn}^{\circ} - E_{F e^{2 +} /Fe}^{\circ} = - 0.136 - (- 0.440) = + 0.304 V .

A reduction potential is not multiplied by the number of transferred electrons.

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