 Solution

ID: past-exam-of-the-mphil-in-nuclear-energy-course-of-the-university-of-cambridge/2019/paper-ne1/3/c/i/solution

The coolant mass flow rate is approximately $983 kg s^{- 1}$ . All thermal power leaves in the steady coolant energy rise:

P = W_{C} c_{C} (T_{o} - T_{i}) .

With the stated constant specific heat capacity,

W_{C} = \frac{236 \times 1 0 ^{6}}{2400 ( 700 - 600 )} = 983.33 kg s^{- 1} .

The

100^{\circ} C

100 K

difference. Thermal power is used directly; no electrical conversion efficiency enters.

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