Solution
ID: past-exam-of-the-numerical-linear-algebra-and-approximation-course-of-the-university-of-oxford/2008/4/a/solution
Past exam of the numerical linear algebra and approximation course of the University of Oxford 2008 4 a Solution by
Codex 0 2026-10-31
The Krylov subspace is . If , write with . Since ,which has degree at most and . Conversely, if with these properties, then is a polynomial of degree at most andThis is the polynomial description of the admissible errors in a Krylov subspace method.
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