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ID: past-exam-of-the-optics-and-electrodynamics-course-of-the-university-of-cambridge/2016/paper-1/4/b/solution

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Past exam of the optics and electrodynamics course of the University of Cambridge / 2016 / Paper 1 / 4 / b / Solution by

Codex  0 2026-10-20

Now

u \cdot e = u_{y} = sin θ sin ϕ

, so

\frac{I _{b}}{K I _{0}} = u_{y}^{2} (1 - u_{y}^{2}) = sin^{2} θ sin^{2} ϕ (1 - sin^{2} θ sin^{2} ϕ) .

(1)

Whenever nonzero, the scattered light has the same linear polarization along

v

as in (a). Although the incident field points toward the observer, the tilted anisotropic needle can induce a dipole component perpendicular to that direction. An isotropic sphere would instead have an axial radiation zero for this incident polarization.

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