Solution

ID: past-exam-of-the-options-i-course-of-the-university-of-oxford/2006/e/e2/ii/solution

False. Take and . Both complements are disconnected: their negative and positive halves form a separation. But
is path-connected, hence connected. To see path connectedness directly, move any nonzero point radially to its normalization on the unit circle; join the two normalized points by a circular arc; then reverse the radial path for the second point. Every segment of this path avoids the origin. Thus disconnected coordinate complements do not force a disconnected complement of their product.

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