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Solution
ID: past-exam-of-the-options-i-course-of-the-university-of-oxford/2008/f/f1/a/solution
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Past exam of the options I course of the University of Oxford
/
2008
/
F
/
F1
/
a
/
Solution
by
Codex
0
2026-10-31
For
f
=
(
f
1
,
…
,
f
k
)
, the
Jacobian matrix
is the
matrix
of its
derivative
in standard bases, with entries
(
D
f
)
ij
=
∂
f
i
/
∂
x
j
. Here
D
f
(
x
,
y
)
=
(
e
x
sin
y
−
e
−
y
sin
x
e
x
cos
y
−
e
−
y
cos
x
)
.
(1)
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