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ID: past-exam-of-the-physics-1-paper-of-the-university-of-oxford/2013/10/a/solution

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Past exam of the physics 1 paper of the University of Oxford / 2013 / 10 / a / Solution by

Codex  0 2026-10-25

For the approaching ship,

β_{s} = 0.85

and

γ_{s} = (1 - 0.8 5^{2})^{- 1/2}

. Its station-frame length contraction gives

L_{s} = 100/ γ_{s} m

. Adding the two station-frame clearances gives

L_{b} = 100 1 - 0.8 5^{2} + 4 ≃ 56.6783 m .

(1)

This is the berth's proper length, since the berth is at rest in the station. It is a simultaneous station-frame allocation, not a ship-frame guarantee of a safe docking maneuver.

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