 Solution

ID: past-exam-of-the-physics-1-paper-of-the-university-of-oxford/2017-resit/8/b/solution

v (0) = v_{0}

gives

v (t) = v_{0} + g t - u lo g \frac{m _{0}}{m _{0} - α t} .

This formula holds during the constant-flow burn, while

m_{0} - α t > 0

and fuel remains. The negative logarithmic term represents the slowing due to upward rocket thrust.

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